can i make a function array with pointers?

[REGFly]

The question is pretty straightforward. I recently came back from a huge break because of exams and now i'm resuming my snake game, but i can't remember how to do this, if i ever even knew how to do this
This is what i wrote:

Code: Select all


int const * menuChoice[] =
{

singleGame(),
multiGame(),
classicGame(),
changeSettings(),
gameCredits(),
terminate(),
 
};



but it dosen't work

[awesome101]

Yeah you can. This is some code for a simple c++ program.

#include <iostream>
using namespace std;

typedef int (*IntFunctionWithOneParameter) (int a);

int function(int a){ return a; }
int functionTimesTwo(int a){ return a*2; }
int functionDivideByTwo(int a){ return a/2; }

void main()
{
IntFunctionWithOneParameter functions[] =
{
function,
functionTimesTwo,
functionDivideByTwo
};

for(int i = 0; i < 3; ++i)
{
cout << functions[i](8) << endl;
}
}

[REGFly]

And if my functions dont take anything or return anything could i declare it like this?
Typedef void (*arrayFunction);

[Myndale]

Close:

Code: Select all

typedef void (*arrayFunction)();